This is in my router's routing table:
Kernel IP routing table
Destination Gateway Genmask Flags Metric Ref Use Iface
192.168.1.0 0.0.0.0 255.255.255.0 U 0 0 0 br0
And this is my host's routing table:
Kernel IP routing table
Destination Gateway Genmask Flags Metric Ref Use Iface
0.0.0.0 192.168.1.1 0.0.0.0 UG 100 0 0 enp0s3
192.168.1.0 0.0.0.0 255.255.255.0 U 100 0 0 enp0s3
and here is the br0 interface of the router:
br0 Link encap:Ethernet HWaddr 24:4B:FE:F0:18:C0
inet addr:192.168.1.1 Bcast:192.168.1.255 Mask:255.255.255.0
UP BROADCAST RUNNING ALLMULTI MULTICAST MTU:1500 Metric:1
RX packets:68370 errors:0 dropped:0 overruns:0 frame:0
TX packets:82681 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:0
RX bytes:7411859 (7.0 MiB) TX bytes:64534493 (61.5 MiB)
How would two hosts in the 192.168.1 subnet communicate with eachother? If they were both only connected to the router with ethernet? Here's how i think it works:
- host at 192.168.1.10 wants to send to 192.168.1.11
- The routing table entry 192.168.1.0 is chosen
- the host will broadcast an arp request for the mac address of 1.11
- The router receives this arp request on its br0 interface
- The bridge interface gets the mac address of 1.11 and sends it back to 1.10?
- The 1.10 host sends a frame with the mac address of 1.11 to the router's br0 interface?
- So does the bridge interface now realize that the mac address is not its own, and then forwards it to the correct host?
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